When a train travels at a speed of 60kmph,it reaches the destination on time.when the same train travels at a speed of 50kmph,it reaches its destination 15min late.what is the length of journey?
a,75km
b,50km
c,60km
d,85km

• (x/50) - (x/60) = 15/60
  then x = 75
• 9 years agoHelpfull: Yes(21) No(0)
• Let x be the time reached with the speed 60km/h
  50km/h ----> x+15
  Distance is equal so
  60(km/h)× xhr = 50(km/h) × (x+15) hr
  So
  60 x = 50x + 750
  So the would be in km
  And x = 75
  So
  75km
• 9 years agoHelpfull: Yes(15) No(2)
• Let x be the time reached with the speed 60km/h
  50km/h ----> x+15
  Dist. is equal so
  60*x= 50*(x+15)
  So
  60 x = 50x + 750
  So the would be in km
  And x = 75km
• 9 years agoHelpfull: Yes(5) No(1)
• d=60*x
  d=50(x+15)
  solve above equations
  we get 75km
• 9 years agoHelpfull: Yes(5) No(1)
• s1=60 kmph, s2=50 kmph, T1=t, T2=t+15
  
  we know that when distance is fixed then speed ratio is inversely proportional to the time taken ratio
  
  so, s1/s2= T2/T1 => 60/50= t+15/t => t=75 min
  
  so total distance = 75/60*60= 75 km
• 9 years agoHelpfull: Yes(3) No(0)
• ans 75km 60t=50*(t+15/60) then t=5/4 length of the journey will 60*5/4=75
• 9 years agoHelpfull: Yes(2) No(0)
• 60/50=t+(15/60)/t
  t=5/4
  distance=60*(5/4)=75 km
• 9 years agoHelpfull: Yes(0) No(0)
• x/50 -x/60=15/60
• 9 years agoHelpfull: Yes(0) No(0)
• may be its 75km.
• 9 years agoHelpfull: Yes(0) No(0)
• 85km,
  Then only it will reach 15min late where the speed is 5okmph
• 8 years agoHelpfull: Yes(0) No(2)
• D=(difference in time * speed * sped2)/difference in speed
  =15/60[(50*60)/10]
  =75Km
• 6 years agoHelpfull: Yes(0) No(0)
• Let the distance be x km.
  Difference in timings = 15 min = 15/60 hr
  => x/50 - x/60 = 15/60
  => 6x - 5x = 30/4.
  => x = 75 km.
• 5 years agoHelpfull: Yes(0) No(0)
• Let x be the distance
  first train reached at station on time
  second train late by 15 min
  so the equation from above case
  60 * x = 50 * (x+15)
  x = 75
• 9 Months agoHelpfull: Yes(0) No(0)