Infosys
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Numerical Ability
Age Problem
0.0023*0.13/0.236=my age
0.022*0.12/0.220=my wife age
then wat is difference b/w ages?
Read Solution (Total 5)
-
- 0.0107 first one reduced to 0.0013 and second one reduced to 0.012 difference between them was 0.0107
- 10 years agoHelpfull: Yes(6) No(0)
- Please explain how it is?
- 10 years agoHelpfull: Yes(1) No(0)
- My age = 0.0023*0.13/0.236 = 0.000299/0.236 = 0.001266949
My wife age = 0.022*0.12/0.220 = 0.00264/0.220 = 0.012
difference b/w ages = 0.012 - 0.001266949 = 0.01073 - 9 years agoHelpfull: Yes(1) No(2)
- Ans : 79/7180
- 10 years agoHelpfull: Yes(0) No(2)
- Please explain the solution.
- 10 years agoHelpfull: Yes(0) No(0)
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