If a man walks a certain distance in 20 days when he rests 10 h each day, how long, will it take him to walk three times as far, if he walks twice as fast and rest 12 h each day?

• case1-
  days=20
  rest per day=10hr
  walks per day=24-10=14hr
  time for 20 days=14*20=280hr
  d=s*t
  d/s=t
  d/s=280 -> 1st equation
  
  case2-
  D=3d where D=new distance and d=old distance
  S=2s where S=new speed and s=old speed
  D=S*T where T=new time
  put the values of D and S
  3d=2s *T
  3d/2s=T
  put the value of d/s from 1st equation
  3/2 * 280 =T
  T=420 hr
  rest per day=12 hr
  walks per day=24-12=12hr
  he is walking 12hrs per day so , he requires 35 days for 420 hrs.
• 10 years agoHelpfull: Yes(4) No(0)
• case 1 : when he rests 10 hrs each day , that means he walks for 14hrs each day .
  that means he walks for 280 hours in total.
  now let the total distance be X. then speed will be x/280.
  
  case2: when he walks 3 times more , then the total distance becomes 3x. also he walks twice as fast , therfore speed in this case will be x/140.
  now the total time taken to cover this distance will be 3x (140/x)= 420 hrs.
  now when he rest for 12 hrs each day , that means he travels for 12 hrs each day.
  therefore total days taken = 420/12=35
• 8 years agoHelpfull: Yes(0) No(0)