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Numerical Ability
Time Distance and Speed
Starting from his house one day, a student walks at a speed of 5/2 kmph and reaches his school 6 minutes late. Next day he increases his speed by 1 kmph and reaches the school 6 minutes early. How far is the school from his house?
1. 1 km
2. 15 km
3. 14 km
4. 3 km
Read Solution (Total 2)
-
- convert minits into hours so 6/60hr
5/2(t+6/60)=7/2(t-6/60)
solve the above eqation t=6/10
then d=s*t
d=5/2(t+6/60)
=5/2(6/10+6/60)
=7/4 km
the above options are wrong - 10 years agoHelpfull: Yes(8) No(1)
- Required Distance is X Km.
Difference in a times taken at two speed is =12min =1/5hr.
now
X/(5/2)-X/(7/2)=1/5
so by solve above equation X=7/4Km
- 10 years agoHelpfull: Yes(2) No(0)
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