Syntel Company Numerical Ability Time Distance and Speed

Starting from his house one day, a student walks at a speed of 5/2 kmph and reaches his school 6 minutes late. Next day he increases his speed by 1 kmph and reaches the school 6 minutes early. How far is the school from his house?
1. 1 km
2. 15 km
3. 14 km
4. 3 km

Read Solution (Total 2)

convert minits into hours so 6/60hr

5/2(t+6/60)=7/2(t-6/60)

solve the above eqation t=6/10
then d=s*t
d=5/2(t+6/60)
=5/2(6/10+6/60)
=7/4 km

the above options are wrong
10 years agoHelpfull: Yes(8) No(1)

Required Distance is X Km.
Difference in a times taken at two speed is =12min =1/5hr.
now
X/(5/2)-X/(7/2)=1/5
so by solve above equation X=7/4Km
10 years agoHelpfull: Yes(2) No(0)

Syntel Other Question

Walking 6/7th of his usual speed, a man is 12 minutes too late. The usual time taken by him to cover that distance is:
1. 2 hour
2. 1 hr 12 min.
3. 1 hr 15 min.
4. 45 min Robert is traveling on his cycle and has calculated to reach point A at 2 PM. if he travels at 10 kmph; he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?
1. 8 kmph
2. 13 kmph
3. 12 kmph
4. 16 kmph