If a train runs at 40 kmph, it reaches its destination late by 11 minutes but if it runs at 50 kmph, it is late by 5 minutes only. The correct time for the train to complete its journey is:
1. 13 min.
2. 17 min.
3. 19 min.
4. 22 min.

• let time be x
  (x+11)*40=50(x+5);
  s=d/t;
  d=t*s
• 10 years agoHelpfull: Yes(2) No(0)
• ans:19
  let time be
  (x+11)*40=50(x+5);
  x=19
• 10 years agoHelpfull: Yes(2) No(0)
• 19 min.
  
  If the distance=x km., Time taken@40 kmph =x/40 and @50 kmph=x/50
  Difference between these two time is (11-5)=6 min.=1/10 hour
  So [(x/40)]-[(x/50)]= 1/6, x=20
  Time taken @ 40 kmph=x/40= 20/40= 1/2 hours=30 min.,which is 11 min late
  So correct time=30-11= 19 min.
  
• 10 years agoHelpfull: Yes(2) No(0)
• let s1=40,s2=50
  t1=t+11,t2=t+5
  then from relation s=(d/t)
  s1/s2=t2/t1,now we can solve it
• 10 years agoHelpfull: Yes(0) No(0)