A and B complete a piece of work in 10 days.B and C in 12 days and C and A in 15 days.All the three of them started working and then B left after 4 days.C left 3 days after that and then immediately B joined A again to complete the remaining work.In how many days was the work
completed?
a)10 b)12 c)14 d)22

• 2(A+B+C)=1/10+1/12+1/15
  A+B+C 1 day work is=1/8
  A+B+C 4 days work is=1/8*4=1/2
  then b is left so the
  remaining work is 1-1/2=1/2
  A+C 1 day work is 1/15
  A+C 3 days work is 1/15*3=1/5
  then C is left so remaining work is=1/2-1/5=3/10
  and B is again add with A to do remaining work
  A+B 1 day work is 1/10
  in x day complete the 3/10 work is
  x=3/10*10=3
  so total 3+3+4=10
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• a) 10 days..
  
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