A father is four times as old as his son. In twenty years, he'll be twice as old. How old are they now?

• age of father is 40 yrs and age of son is 10 yrs.
  
  
  If F is age of father and s is age of son
  f=4s
  f+20 = 2*(s+20)
  4s+20 = 2s+40
  2s=20
  s=10
  F=40
• 12 years agoHelpfull: Yes(10) No(0)
• Son's age=10
  Father's age=10*4=40
  After 20years,
  Son's age=10+20=30
  Father's age=40+20=60
  Therefore, father's age is twice as son's age.
• 12 years agoHelpfull: Yes(4) No(0)
• let father age=x and son age=y
  then x=4y
  20 years then:
  x+20=2(y+20)
  4y+20=2y+40
  thus present age y+20=30 x+20=60
• 12 years agoHelpfull: Yes(2) No(4)
• Ans= Father-40:Son-10
  Exp: Let X=father's age and Y=Son's age
  X=4(Y)
  In 20years,
  2(Y)=X+20
• 12 years agoHelpfull: Yes(2) No(0)
• son is 10 years old
  father is 40
• 9 years agoHelpfull: Yes(0) No(0)
• son is 10 years old
  father is 40
• 9 years agoHelpfull: Yes(0) No(0)
• son is 10 years old
  father is 40
• 9 years agoHelpfull: Yes(0) No(0)
• son is 10 years old
  father is 40
• 9 years agoHelpfull: Yes(0) No(0)
• son is 10 years old
  father is 40
• 9 years agoHelpfull: Yes(0) No(0)
• son is 10 years old
  father is 40
• 9 years agoHelpfull: Yes(0) No(0)
• son is 10 years old
  father is 40
• 9 years agoHelpfull: Yes(0) No(0)
• son is 10 years old
  father is 40
• 9 years agoHelpfull: Yes(0) No(0)
• son is 10 years old
  father is 40
• 9 years agoHelpfull: Yes(0) No(0)