total no. of players is 99 other than me.50 plays soccer,45 plays basket ball,50 play valley ball.15 play all three. How many will play only 2 games/

• let A=soccer players..B=basket ball players..C=vollyball players
  n(A U B U C)=n(A) + n(B) + n(C) - n(A INTERSECTION B) - n(A INTERSECTION C) - n(C INTERSECTION B) + n(A INTERSECTION B - INTERSECTION C)
  therefore..
  100=50+45+50-intersections+15
  hence..intersections=145-100+15=60play only 2 games..
• 12 years agoHelpfull: Yes(46) No(12)
• s=play soccer
  b=play basketball
  v=play volliball
  
  50S + 45B + 50V - 15(SBV)= no of ppl who play games atlest one or two
  now,
  no of ppl who play two games = no of ppl who play games atlest one or two -100 + 15 = 15
  
  
  
• 12 years agoHelpfull: Yes(8) No(13)
• let A = soccer, B = basket, C = volleyball players
  n(A U B U C)=n(A)+n(B)+n(C)-n(A intersection B)-n(B inter.. C)-n(A inter.. C) + n(A inter.. B inter.. C)
  
  hence,
  100=50+45+50-intersections+15
  
  => intersections = 60
  
  thus, 60 players play 2 games....and out of which 15 play all 3 games.
  hence, no. of players those will play only 2 games = 60-15 = 45. ANS.
• 11 years agoHelpfull: Yes(1) No(1)
• Let the people who play only two games be : x (Soccer and basketball) y(soccer and volleyball) z(Volleyball and basketball) Therefore, 100 = 50 + 45 + 50 -(x+15) -(y+15) -(z+15) + 15. Solving, we get x+y+z=15.
  
• 10 years agoHelpfull: Yes(0) No(0)
• total =99 + 1 =100
  S + V + B +S^V^B-(S^V + V^B + S^B)=Total
  50 + 45 + 50 +15 - x =100
  160 - x = 100
  x=60
  so, 60 members play only 2 games...
  
• 10 years agoHelpfull: Yes(0) No(0)