If two dies are thrown simultaneously what is the prob. of one of the dice getting face 6 ?
a. 11/36 b. 1/3 c. 12/35 d. 1/36

• a. 11/36
  
  Sample space for two dice = 36
  
  Probability of getting one of the dice 6 is,
  n={(1,6)(2,6)(3,6)(4,6)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)}=11
  n=11
  
  Probability = Total possibilities(n)/Sample space
  P = 11/36
  
• 12 years agoHelpfull: Yes(1) No(0)
• (1,6);(2,6).........(6,6);(6,1)...................(6,5).
  So 11
  and total event 6*6=36
  so p=11/36
• 10 years agoHelpfull: Yes(0) No(0)
• 1/6 * 2C1=1/3.....
• 10 years agoHelpfull: Yes(0) No(0)