The average of seven consecutive even numbers P,Q,R,S,T,U,V is 64. What is the product of P and V?

a) 4060 b) 3860 c) 4260 d) 4440

• x+x+2+x+4+x+6+x+8+x+10+x+12=64*7
  7x+42=448
  x=58
  
  58*70=4060
• 13 years agoHelpfull: Yes(11) No(1)
• In case the average of the given seven consecutive numbers is 64, logically it should be equal to the number exactly equidistant from both ends which is S.
  (For example consider 2,4,6,8,10,12,14. In this case average is 2+4+6+8+10+12+14/7 = 56/7 = 8. This is nothing but the middle number 8 which is fourth in position from both the ends. Note: This method of finding average can be applied to any consecutive even number series when the number of terms is an odd number.)
  Therefore S = 64.
  If S is 64, then P must be 58 and V is 70. Product of 58 and 70 is 4060.
  
• 12 years agoHelpfull: Yes(3) No(0)
• they are consecutive even so S = 64
  so P = 58
  and V = 70
  so P*V = 58*70=4060
• 10 years agoHelpfull: Yes(0) No(0)