There are coins of Rs.5, 2,1,50p,25p,10p,5p. Each one has got a weight. Rs 5 coin weighs 20gms.find the minimum number of coins to get a total of 196.5gms.

• Explanation:
  Rs. 5 taken 9 coins = 9 x 20 = 180 gms
  Rs. 2 taken 2 coins = 2 x 8 = 16 gms
  10paise taken 1 coin= 1 x 0.5= .5 gms
• 12 years agoHelpfull: Yes(15) No(39)
• Rs 5 coin = 20 gm (5*4)
  RS 2 coin= 8 gm(2*4)
  similarly Rs 1 coin = 4gm, 50paise= 2gm, 25 paise= 1gm, 10 paise= 0.4gm, 5paise =0.2 gm
  So we could get 196 gm by taking 9 coins of rs 5 and 2 coins of rs 2. However we could never obtain that additional 0.5 gm . (Odd could not be obtained by adding evens). Hence we could never obtain the mentioned weight :P
  
• 9 years agoHelpfull: Yes(5) No(2)
• Ans: 60
  
  
  
• 9 years agoHelpfull: Yes(1) No(5)
• Rs 5 coin = 20 gm (5*4)
  RS 2 coin= 8 gm(2*4)
  Similarly
  Rs 1 coin = 4gm
  50paise= 2gm 25 paise= 1gm
  10 paise= 0.4gm
  5paise =0.2 gm
  
  We want weight of 196.5
  
  5Rs 9 Coins = 9*20 (No of Coins * Weight) =180 gm
  2Rs 2 Coins = 2*8 (No of Coins * Weight) =196 gm
  5Paisa 2 Coins = 2*0.25 (No of Coins * Weight) =196.5 gm
  
• 8 years agoHelpfull: Yes(0) No(1)