A very big story.on Tuesday college parking place have only 4wheelers & bicycles,total no of wheels was 182,yhen what is the possible no of bicycles?

• Both options 2 and 4 are possible.
  Let 'f' be the fourwheelers and 'b' be the bicycles
  Then,
  4f+2b = 182 If b = 20, 4f=142 So, f is not an integer..hence this option is not valid If b = 19, 4f+2b = 182
  
  If b = 20,
  4f=142
  So, f is not an integer..hence this option is not valid
  
  If b = 19,
  4f = 144
  So, f = 36, an integer (VALID)
  
  If b = 18,
  4f = 146,
  So, f is not an integer (NOT VALID)
  
  If b = 17,
  4f = 148
  f is an intger (VALID)
• 12 years agoHelpfull: Yes(5) No(0)
• 91 possible number of bicycles.
  Consider, there is no 4wheelers in parking.
  So, No. of wheels/2
  =182/2
  =91
• 12 years agoHelpfull: Yes(2) No(2)
• Soln. = 89 possibles of bicycles..
  Expln.= Total Wheels, X=182
  Four Wheelers must contain 4 wheels as Y
  Two Wheelers must contain 2 wheels as Z
  Therefore Max(Z)=???
  =X - Min(Y)/2
  =182-4/2
  =178/2
  =89..
  
  $ Vignesh(India,TamilNadu) $
• 12 years agoHelpfull: Yes(1) No(6)