Simple question but big one on average age's like a,b,c weighted separately 1st a,b,c ,then a& b, then b&c ,then c&a at last abc, the last weight was 167,then what will be the avg weight of the 7 weight?

• ((a+b+c)+(a+b)+(b+c)+(c+a)+(a+b+c))/7=>4(a+b+c)/7=>4*167/7=>95.43
• 13 years agoHelpfull: Yes(2) No(0)
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  We can collect like terms in the numerator:
  
• 12 years agoHelpfull: Yes(0) No(0)
• first average of 7 weight = (first a , b, c seperately)+ (a+b)+(b+c)+(c+a)+(a+b+c)
  that is = (a+b+c)+(a+b)+(b+c)+(c+a)+(a+b+c)/7
  =4(a+b+c)/7
  and last weight is 167 means (a+b+c) = 167
  =(4*167)/7
  =95.42857
• 12 years agoHelpfull: Yes(0) No(0)