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Swetha, Tina, Uma and Vidya are playing a gambling. In this different people lose in different games-in the reverse alphabetical order. The rule is that if one loses she should double the amount of others. At the end of 4th game each of them have same amount of money (Rs.32).
Which one of them started with the least amount?
(a) Which one of them started with the largest amount of money?
(b) At the end of the 2nd game what is the amount of money with uma?
Read Solution (Total 4)
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- Swetha has started with least amount of Rs10
Vidya has started with largest amount of Rs66
At the end of second game uma has Rs8
Initially Swetha=Rs10, Tina= Rs 18, Uma = Rs 34, Vidya =Rs 66 - 10 years agoHelpfull: Yes(2) No(5)
- Vidya, Swetha, Rs.8
- 10 years agoHelpfull: Yes(1) No(2)
- least amt-swetha(4)
largest amt-vidya(72)
uma-2nd game=72
- 8 years agoHelpfull: Yes(1) No(0)
- largest amount-vidya
uma have -rs 8 - 5 years agoHelpfull: Yes(0) No(0)
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