If the clock(Conventional clock with numbers from 1 to 12 in order) is cut into 3 pieces such that the sum of numbers on each piece are in Arithemetic Progression(A.P) with a common difference of 1.

• The sum of the numbers 1 to 12 = (1 + 12)(2 + 11)(3 + 10) ... (6 + 7). That's 6 sets of 13 = 78.
  
  Divide that by 3 and you get an average of 26.
  
  So you need each section to add to 25, 26 and 27 respectively.
  
  I assume you have to keep consecutive numbers together... one way to do that is:
  
  3, 4, 5, 6, 7 = 25
  8, 9, 10 = 27
  11, 12, 1, 2 = 26
  
  The sum of the even numbers in the group where 5 is present {3, 4, 5, 6, 7} is 4 + 6 = 10.
  
  The answer is B) 10.
• 10 years agoHelpfull: Yes(4) No(0)
• Ans:10
  
  in the pieces, the numbers will be distributed in the following way
  {3,4,5,6,7} [sum. 25]
  {8,9,10} [sum. 27]
  {11,12,1,2} [sum. 26]
• 10 years agoHelpfull: Yes(0) No(1)