There are 4 cities A,B,C,D.There are 4 Routes from A to B,3 routes from B to C,and 2 routes from C to D.Then in how many different ways we can go from A to2 D
A)12 B)24 C)32 D)48

• 24 ROUTES..
  
  Explaina: A to B= 4 Routes(P,Q,R,S)
  B to C= 3 Routes(T,U,V)
  C to D= 2 Routes(W,X)
  Therefore, differen ways from A to D is
  (PTW,PTX,PUW,PUX,PVW,PVX),(QTW,QTX,QUW,QUX,QVW,QVX),(RTW,RTX,RUW,RUX,RVW,RVX),
  (STW,STX,SUW,SUX,SVW,SVX) = 24
  
  
  In other Method= 4c1= 4*3*2*1
  = 24
• 13 years agoHelpfull: Yes(6) No(0)
• simple 4*3*2=24
• 10 years agoHelpfull: Yes(3) No(0)
• Since A-B =4
  B-C=3
  C-D=2
  A-D will be A*B*C*D Values i.e 4*3*2=24
• 8 years agoHelpfull: Yes(0) No(0)