CTS Company Numerical Ability Algebra

In a club there are certain no. of males and females. If 15 females are absent then no. of males will be twice that of females. If 45 males are absent then female strength will be 5 times that of males. Find no. of males actually present.

Read Solution (Total 2)

males-50
females-40
11 years agoHelpfull: Yes(2) No(2)

15 females are absent m = 2*(f-15) -> equ I

45 males are absent f - 15 = 5*(m-45) -> equ II

=> f = 5*(m-45) + 15

=> m = 2*((5*(m-45)+15)-15)

=> m = 2*(5m - 225 +15 - 15)

=> m = 2*(5m-225)

=> m = 10m - 450

=> 9m = 450

=> m = 50

so from equation II

f - 15 = 5*(m - 45)

=> f - 15 = 5*(50-45)

=> f - 15 = 5*(5)

=> f = 25 + 15

f = 40
10 years agoHelpfull: Yes(2) No(0)

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