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Three men A, B, C plays Cards. If one loses the game he have to give Rs.3. If he wins the game he will gain Rs.6. If A has won 3 Games, B loses Rs.3, C wins Rs.12.What is the total no. of games played?
Read Solution (Total 10)
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- answer:6 games
A-wins 3,B-lose 1,c-wins 2
total=3+1+2=6 - 11 years agoHelpfull: Yes(10) No(9)
- A won 3 matches=3
c wins rs.12, hence it won 2 matches=2
b loses 3 rs. thus out of 5 matches(A+C)above b lose 15rs.(5*3rs) hence it won 2 matches(wins 12rs), so the difference is 3rs.(15-12) which it lost. thus 3+2+2=7 - 8 years agoHelpfull: Yes(6) No(0)
- A - 3 wins 11 losses
B - 5 wins 9 losses
C- 6 wins 8 losses.. so total 14 games. - 11 years agoHelpfull: Yes(5) No(5)
- 5 games i guess.
A won 3 games = 3 games played
C won Rs.12 means = 2 games played
So, total = 5games - 13 years agoHelpfull: Yes(4) No(13)
- ques. is wrong c must win 15 rs.
- 8 years agoHelpfull: Yes(2) No(0)
- 10 hai uuihiuh
- 10 years agoHelpfull: Yes(1) No(2)
- total matches is 11,If B wins 3 matches then he will get 6*(3)=18Rs in other side loses 8 matches then he loses 3*(8)=24Rs.So net total of B rupees is 18-24=-3Rs.”Negative sign indicates loses”which is same as per question,Then for C,he wins 5 matches i.e gain of 6*(5)=30Rs and lose 11-5=6 matches then we have to calculate paisa for C i.e. how much he loose 3*(6)=18Rs.Thus net total for C rupees is 30Rs-18Rs=+12Rs,”+ sign indicates gain”and lastly for A he wins 3 matches i.e. 6*3=18Rs,similarly loses 11-3=8 matches.In sort A=(3)Win 8Loss,for B=3Win 8Loss n for C=5Win 6Loss…Here I m not calculating Rs for A cause we want total no of card matches!!!
- 10 years agoHelpfull: Yes(1) No(2)
- Total 7 games
because A won 3 games + C won 2 games= 5 games
B only loses 3 Rs i.e. he played already 5 games ->15 Rs loss
so,now next two games hi won then he gain 12 Rs
15 Rs - 12 Rs = 3Rs - 8 years agoHelpfull: Yes(1) No(0)
- totally 6 games are played.
A won 3 games
B lose Rs .3-1times
c wins 12 -2 times - 8 years agoHelpfull: Yes(1) No(0)
- 13 no of games played
- 6 years agoHelpfull: Yes(0) No(1)
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