A can swim & cross 50m(the length of swimming pool) in 2 min. B can swim & cross 50m in 2min 15sec. Every time when they meet a bell gong is struck. For 2000m how many bell sounds might be produced?

• answer:41 times
• 11 years agoHelpfull: Yes(3) No(1)
• A swims 50mts in 2mins*60=120secs;
  B swims 50mts in 2.15mins*60=135secs;
  To swim 2000mts, 50mts*40times=2000mts;
  so A swims for 120secs*40times=4800secs;
  so B swims for 135secs*40times=5400secs;
  The common factor for 120secs,135secs is 1080secs.
  For A, 4800secs/1080secs=4.4(app 4)
  For B, 5400secs/1080secs=5
  Therefore A and B meet 4 times and hence bell will struck 4
  times...........
• 11 years agoHelpfull: Yes(1) No(1)
• Please can any body give correct solution
• 8 years agoHelpfull: Yes(0) No(0)
• Taking LCM of 120 and 135 seconds we get 1080 seconds i.e. 18 minutes; they both meet every 18 minutes.
  Now speed of A = 25 m/min and B = 200/9 m/min. A will take 80 minutes to cover 2000 m and B will take 90 minutes for the same.
  80 being the smaller value; 4X18 = 72.
  Therefore. answer = 4 times.
• 8 years agoHelpfull: Yes(0) No(0)