29. The perimeter of a rhombus is 52 units. One of its diagonal is 24 units. What is its second diagonals length?
Ans: 10

• When the perimeter of a triangle is 52 units each side is 13 units
  Next, the diagonal of a rhombus bisect each other at 90 degree
  Thus the half of the diagonal is 12 units
  Now in a right angle triangle so formed, the perpendicular is 12 and the hypptenuse is 13(that is the side of the triangle)
  Finding the base(which is half of the other diagonal):
  13^2-12^2 =25
  Thus half of the diagonal is 5 and the diagonaL IS 10UNITS
• 12 years agoHelpfull: Yes(29) No(1)
• The thing about a rhombus is that its sides are all equal, so the length is 13, and the diagonals bisect each other, at a right angle.
  If you draw a rhombus, you see that the diagonals make 4 right angled triangles, and you have the length of two sides (one 12 and the other 13), so half the remaining diagonal has to be 5 i.e.sqrt(13^2-12^2)=5
  2nd diagonal lenth=2*5=10
• 11 years agoHelpfull: Yes(9) No(0)
• Take PQRS is a point of rhombus .
  1st Diagonal PR=24 units
  2nd Diagonal QS
  now take O as a center of Diagonal PR . so , PO=24/2=12
  we know that side of rhombus is equal.
  so perimeter/4= 52/4 =13
  so PQ=13
  now QO find by pythagoras theorem =5
  so QS =2 * QO =10
  
  ANS=10
• 7 years agoHelpfull: Yes(2) No(0)
• Diagonal of rhombus=2¤{d1^2+d2^2}=52
  52/2=26
  0ne of diagnal is 24.
  so 24^2+x^2=26^2
  =676
  X^2=676-576=100
  
  So x=10
• 7 years agoHelpfull: Yes(0) No(1)
• formula is:
  (side)^2=(d1/2)^2+(d2/2)^2
  side=perimeter/4=52/4=13
  d1/2=24/2=12
  therefore, d2/2=5 units
  hence, d2=5*2=10 units
• 7 years agoHelpfull: Yes(0) No(0)