27. In a rectangle the length is increased by of the original length. By what proportion should the width be reduced
so that the area will be the same?
Ans: 33

• statement is incomplete.
  In a rectangle the length is increased by of the original length.
  
  Here proportion of increase of length is not specified.
  If length is increased by 100% of original length, new length will become double of original length.
  
  
  If l and b are earlier length and breadth and
  L and B are final length and breadth
  then
  l*b= L*B
  l*b = 2*l*B
  B= b/2
  
  New width will be half of original width.
  
  
  
• 12 years agoHelpfull: Yes(20) No(2)
• In the given problem length is increased by 50% so to get the same value breadth is decreased. 33 1/3%.
• 10 years agoHelpfull: Yes(4) No(4)
• Assume the original Length and Breadth as 5 and 4. The area is 5 * 4 = 20.
  
  The new length is 5 + 5 = 10. To retain the same area the breadth should be 2.
  
  Breadth reduced from 4 to 2 or 50%
• 8 years agoHelpfull: Yes(1) No(0)
• assume length and width of rectangle are 'L' and 'W' .So area will be 'LW' .Now according to the condition
  length is increased by the original length i.e. (L+L=2L).To make area equal to original area(LW) we need to half of width i.e. (W/2).
• 7 years agoHelpfull: Yes(0) No(0)
• Solution 1
  
  Let length =
  10
  
  width
  =
  10
  
  Then, area
  =
  10
  ×
  10
  =
  100
  
  
  New length
  =
  14
  
  Therefore, new width
  =
  100
  14
  
  
  Decrease in width
  =
  10
  −
  100
  14
  =
  20
  7
  
  
  Required percent
  =
  (
  20
  7
  )
  10
  ×
  100
  =
  200
  7
  %
  =
  28
  4
  7
  %
• 5 years agoHelpfull: Yes(0) No(1)