self
Maths Puzzle
A father i know,is 4 times his son,s age.And in 30 years son's age will be half of his fathers age.How old are the father and son now.
Read Solution (Total 3)
-
- present ages of father and son be 4s,s
s+30=(4s+30)/2
=>s=15
present age of son, s=15 and present age of father, 4s=60. - 13 years agoHelpfull: Yes(0) No(0)
- Ans. Father = 60 years and son = 15 years
Let father's present age is 4x then sons age is x.
After 30years age of father will be 4x+30 and sons age will be x+30.
As per the given condition x+30 = (1/2)*(4x+30) => x+30=2x+15 => x = 15
So sons present age is 15 years and that of father is 4*15 = 60 years. - 13 years agoHelpfull: Yes(0) No(0)
- let x be the father's age and y be the son's age
x/2=y
(x-30)=4(y-30)
2y-30=4y-120
120-30=4y-2y
2y=90
y=45 so,x=90
before 30 years, y=15 x=60 - 12 years agoHelpfull: Yes(0) No(0)
self Other Question