There are two sections in a question paper each contain five questions. A student has to answer 6 questions. Maximum no. of questions that can be answered from any section is 4. How many ways he can attempt the paper?

(a) 50
(b) 100
(c) 120
(d) 200

• If the max number from each section is 4 and a total of 6 questions must be answered then the possible ways to answer are:
  
  4 from A and 2 from B
  
  or 2 from A and 4 from B
  
  or 3 from both A and B
  
  Number of ways of choosing 4 from part A AND 2 from part B = 5C4 * 5C2 = 50 ... (AND means multiply)
  
  Number of ways of choosing 2 from part A AND 4 from part B = 5C2 * 5C4 = 50
  
  Number of ways of choosing 3 from part A AND 3 from part B = 5C3 * 5C3 = 100
  
  
  So total number of ways to answer the paper = 50 + 50 + 100 = 200
  ........ option (d)
• 12 years agoHelpfull: Yes(38) No(0)
• 5C4*5C2=50
  5C3*5C3=100
  5C2*5C4=50
  50+100+50=200
• 12 years agoHelpfull: Yes(7) No(0)
• (d) 200 should be correct.
• 12 years agoHelpfull: Yes(3) No(0)
• (d)200 ans.
  sol:-
  Student can choose from the two sections as:
  s1(5) s2(5)
  ----- -----
  2 4
  3 3
  4 2
  hence,p(E)=5C2*5C4+5C3*5C3+5C4*5C2=50+100+50=200 ANS.
• 12 years agoHelpfull: Yes(3) No(0)
• 5c4+5c2=65.
  5c3+5c3=40.
  5c2+5c4=65.
  65+40+65=170.
  5c1=120.
  therefore the prob. of attempting is 170-120=50.
• 12 years agoHelpfull: Yes(0) No(16)
• 4 from A and 2 from B
  
  or 2 from A and 4 from B
  
  or 3 from both A and B
  
  Number of ways of choosing 4 from part A AND 2 from part B = 5C4 * 5C2 = 50 ... (AND means multiply)
  
  Number of ways of choosing 2 from part A AND 4 from part B = 5C2 * 5C4 = 50
  
  Number of ways of choosing 3 from part A AND 3 from part B = 5C3 * 5C3 = 100
  
  
  So total number of ways to answer the paper = 50 + 50 + 100 = 200 → choice (d)
  
• 9 years agoHelpfull: Yes(0) No(1)