a+b+c=0, then roots of ax^2+bx+c = 0 is
Option
a) imaginary
b) real
c) coincidental
d) zero

• Ans is Real Values.
  
  Roots of the quadratic equation are
  x = [-b +/- sqrt(b^2 - 4ac)] / 2a ................... [1]
  
  Since, a+b+c = 0 ==> b = -(a+c)
  b^2 = (a+c)^2 = a^2+c^2 +2ac
  b^2 -4ac = a^2+c^2-2ac = (a-c)^2 ........... [2]
  
  From [1] and [2], we get,
  x = [a+c +/- (a-c)] / 2a
  
  Solving above, X roots are 1 and c/a
  ROOTs are Real
• 12 years agoHelpfull: Yes(19) No(1)
• Roots are real
• 10 years agoHelpfull: Yes(2) No(0)
• b=-(a+c)
  ax^2+bx+c
  ax^2-ax-cx+C
  ax(x-1)-c(x-1)
  (ax-c)(x-1)
  x=c/a,1 real roots
  
• 10 years agoHelpfull: Yes(1) No(0)
• Take c=0,a=1,b=-1
  so x^2-x=0
  x=+1,-1
  so real
  
• 10 years agoHelpfull: Yes(1) No(0)
• x=1 only is the solution as 1 is a real number ans is real
• 10 years agoHelpfull: Yes(0) No(0)
• x=1 so roots are real
• 10 years agoHelpfull: Yes(0) No(0)
• 2.real
  a+b+c=0
  root
  alfa=-b/a,
  beta=c/a
  so,its roots should be real
• 10 years agoHelpfull: Yes(0) No(0)
• the roots will be either 1 or c/a (use the formula to calculate roots)
  hence ans=b i.e, real roots
  
• 10 years agoHelpfull: Yes(0) No(0)