Q. A monkey climbs 6 mts and falls 3mts in alternate minutes.Then
time taken to climb a tree 60metres high?

• 37 mins
  
  A monkey climbs 6 mts and falls 3mts in alternate minutes. Means in 2 minutes distance convered is 3mts.
  In 36 mins distance covered is 54 meters. on 37th minute it reaches to 60 meters
  
  
• 12 years agoHelpfull: Yes(54) No(4)
• the monkey goes up 6m in 1 minute and comes down 3m in the next minute
  so, the monkey will climb up 3 metres in every 2 minutes
  but here is a trick, if the monkey reaches the top, it will not come down again!
  so substract 6 metres from 60 metres, u will get 54 metres
  then the monkey will go up 54 metres in 36 minutes, rest 6 metre, he will take 1 minute
  so, total 37 minutes :)
• 11 years agoHelpfull: Yes(23) No(0)
• 3 mts ---> 2min
  1 mts ---> 2/3
  60-6=54
  54 mts --> 54*2/3=36
  therefore time req = 36 + 1=37min
• 11 years agoHelpfull: Yes(13) No(1)
• monkey climbs 6 mts and falls 3mts in alternate minutes.
  so in 2 mints monkey climbs (6-3)=3 meters. in the last climb monkey does fall 3mts.so (60-6)=54mtrs climbs in (54/3)*2=36 mins.
  so the last 37th mins monkey reach 60 mtrs.
• 12 years agoHelpfull: Yes(7) No(1)
• ans:40 mints
  in 2 mints it climbs [6-3] mts
  time taken to climb 60mts=60*2/3=40 mints
• 12 years agoHelpfull: Yes(3) No(25)
• height climbed every min =6-3=3 mts
  in 18 min, height climbed=3*18=54 mts
  in 19th min,height climbed=6 mts
  total height climbed in 19 min =54+6=60 mts.
  hence ans=19 min.
• 10 years agoHelpfull: Yes(0) No(3)