In a race from pt. X to pt Y and back, Jack averages 0 miles/hr to pt Y and 10 miles/hr back to pr X. Sandy averages 20 miles/hr in both directions. If Jack and Sandy start race at same tIme, who'll finish 1st
Jack/Sandy/they tie/Impossible to tell

• The question will be
  In a race from pt. X to pt Y and back, Jack averages 30 miles/hr to pt Y and 10 miles/hr back to pr X. Sandy averages 20 miles/hr in both directions. If Jack and Sandy start race at same tIme, who'll finish 1st.
  
  Sandy won the race.
  
  Jack: Runs at 30 mph to Y and at 10 mph back to X. So his avg. speed is given by the formula (2ab)/(a+b) i.e. 15 mph
  
  Sandy: Runs at 20 mph to Y and at 20 mph back to X. So his avg. speed is 20 mph
  
  
  So only Sandy wins the race.
  
  
• 12 years agoHelpfull: Yes(75) No(0)
• Jack will finish first because starting and ending both point are same and here Jack is static by nature so he will finish first
• 12 years agoHelpfull: Yes(11) No(43)
• quesyion incomplete ????? 30????
  
• 8 years agoHelpfull: Yes(3) No(0)
• Sandy is first
  
• 8 years agoHelpfull: Yes(2) No(1)
• d= distance
  Jack's time = d/30 + d/10 = 4d/30 = 2d/15 = 0.1333... d
  Sandy's time = d/20 + d/20 = d/10 = 0.1d
  so finally they tie
  ans : option 3
• 8 years agoHelpfull: Yes(1) No(4)