From a vessel on the first day, 1/3rd of the liquid

evaporates. On the second day 3/4th of the remaining liquid

evaporates. what fraction of the volume is present at the end of

the II day.

• Liquid remained on the first day 1-1/3=2/3
  Liquid remained on the second day = 2/3-(2/3)*(3/4)=1/6 [ans]
• 14 years agoHelpfull: Yes(20) No(4)
• liquid on 1st day 1-1/3=2/3
  liq remained on 2nd day 2/3-3/4=1/2
  
  ANS=1/2 or 50%
• 12 years agoHelpfull: Yes(15) No(16)
• Take on the first day of the liquid volume=v,
  end of the first day of the liquid volume = v-v/3=2v/3,
  end of the second day of the liquid volume = 2v/3 - [(2v/3) *(3/4)]=2v/3 - v/2=v/6 ,
  Therefore The fraction of the volume is '1/6th' present at the end of the II day.
  
• 14 years agoHelpfull: Yes(11) No(2)
• 1st day 1/3 remaining 1-1/3 = 2/3
  2nd day 3/4 of 2/3 = 1/2
  so remaining at d end of 2nd day is (2/3)-(1/2)=1/6
  in %age 16.6666
• 12 years agoHelpfull: Yes(6) No(0)
• Remaining liquid at the end of first day=1-1/3=2/3.
  On second day 3/4th of the remaining 2/3 liquid evaporate.i,e 2/3-(2/3)*(3/4). (2/3)-(6/12)=(2/3)-(1/2). Considering the LCM between 3 and 2,we get 6.so (2/3)-(1/2)=(4-1)/6=(3/6)=1/2= 50%
• 12 years agoHelpfull: Yes(5) No(15)
• Second day = 3/4 * 2/3 = 1/2
  Hence remaining is 1-1/2 = 1/2
• 9 years agoHelpfull: Yes(1) No(1)