If a tap could fill entire tank in 18 hrs due to leakage, then in how much time
tank can be emptied by leakage if tap can fill entire tank in 12 hrs without leakage

• time take to fill[withleakage] =18hrs so workdone in 1hr=1/18
  time tkae to fill[without leakage]=12hrs so workdone in 1hr=1/12
  if u subtract both u'll get time taken by leakage to empty...
  1/18-1/12=1/36 so 36 is ans...
• 12 years agoHelpfull: Yes(19) No(0)
• 1/12- 1/18= 1/36 So the time is 36 Hrs.
• 12 years agoHelpfull: Yes(6) No(0)
• 1/12-1/18=leakage. Ans will be 36 hrs.
• 9 years agoHelpfull: Yes(2) No(0)
• ans) 7.2 hrs
  
  (1/A)-(1/B)=1/18
  and (1/A)=1/12
  using two equations we get B= 7.2 hrs
• 10 years agoHelpfull: Yes(0) No(23)