The least number which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is:
A. 4562
B. 15110
C. 2135
D. 7589

• 
  Solution :Here (48 - 38 ) = ( 60 - 50 ) = ( 72 - 62 ) = ( 108 - 98 ) = ( 140 - 130 ) = 10 in every case
  
  Leat number will be LCM of ( 48, 60, 72, 108, 140 ) - 10
  
  LCM = 15120
  
  So, required number = 15120 - 10 = 15110
• 10 years agoHelpfull: Yes(31) No(1)
• B. 15110
  Go through option
  
• 10 years agoHelpfull: Yes(5) No(4)
• HI Friends, did any one Write CTS amcat exam on last sunday......
• 10 years agoHelpfull: Yes(4) No(2)
• 
  Here (48 - 38) = 10, (60 - 50) = 10, (72 - 62) = 10, (108 - 98) = 10 & (140 - 130) = 10
  ∴ Required number = (L.C.M. of 48, 60, 72, 108, 140) – 10 = 15120 – 10 = 15110
• 8 years agoHelpfull: Yes(1) No(1)
• by hit and trial choose one no. from 48,60...
  here i choose 60 and then divide the options and Answer is 15110
  
• 10 years agoHelpfull: Yes(0) No(2)