Miscellaneous Company Exam Company

Find out the sum of digits. Let A= 19991999 B = sum of digits of A, C = sum of digits of B, D = sum of digits of C

Read Solution (Total 2)

B = 56(1+9+9+9+1+9+9+9)
C = 11(5+6)
D = 2(1+1)
12 years agoHelpfull: Yes(5) No(0)

b=56 it has 2 digits
c=11 it has 2 digits
d=2 it has 1 digit
so ans is 1
11 years agoHelpfull: Yes(3) No(4)

Miscellaneous Company Exam Other Question

There are three guys who have equal number of bullets. All of them shoot 4 bullets. The remaining bullets are equal to the total number of bullets remaining is equal to the bullets each had after division. What was the original number of bullets each one had? Take a marker and start from a corner of a cube. How many edges you can trace if you dont move the marker twice anywhere and never remove it? (You can move the marker only on the corner and edges)