In how many ways can you distribute 6 prizes among 5 children if every child must get atleast one?

• 5 Prizes can distribute to 5 children by 5! ways
  6 prize (last prize) can be given to any one of child. So there are 5 ways to distribute the sixth gift among 5 children.
  
  So the total no.of ways are 5!+5 = 120+5 = 125 Ways
• 12 years agoHelpfull: Yes(56) No(18)
• n items can be distributed among r person such that r>=1 in (n-1)C(r-1) ways >>
  here n=6,r=5>> ans=5C4=5 ways.....(right answer)
  
• 11 years agoHelpfull: Yes(18) No(4)
• 5 Prizes can distribute to 5 children by 5! ways
  6 prize (last prize) can be given to any one of child. So there are 5 ways to distribute the sixth gift among 5 children.
  
  So the total no.of ways = 5* 5! = 120*5 = 600
• 12 years agoHelpfull: Yes(9) No(37)
• 5 because when each student have atleast one prize and only one prize is left and it can only be given to 5 student in 5 ways
• 12 years agoHelpfull: Yes(9) No(14)
• 6 prizes can be distributed to 5 students - 6 * 5*4*3*2 .... This question is same as , how many 5 digit numbers u can make using 6 digitis(repetation not allowed) .. So the answer is 720
• 10 years agoHelpfull: Yes(5) No(11)
• 6^5
  there are 5 ways of distributing 6 prizes among 5 children so 6*6*6*6*6 = 6^5
• 10 years agoHelpfull: Yes(4) No(16)
• This can be found by calculating the reverse case.
  That is we calculate the number ways of prize distribution in which all prizes are given to any one person.
  No. of ways of doing this = 5C1
  And total number of ways of prize distribution = 5×5×...×5 = 5^6
  So the answer = 5^6 - 5C1 = 5^6 - 5 = 15620
• 3 years agoHelpfull: Yes(0) No(0)