In how many ways can you distribute 5 prizes among 6 children if every child must get atleast one?

• not possible..[there are only five children and we have to distribute atleast(means one children got a min prize of one) one prize..which is not possible..]
• 12 years agoHelpfull: Yes(8) No(6)
• I am so sorry...actually the positions of '5' and '6' will be swapped...
• 12 years agoHelpfull: Yes(3) No(4)
• Not possible.
  Because there are 5 prizes and 6 children.
  
  How everyone can get atleast one prize ?
• 12 years agoHelpfull: Yes(2) No(1)
• not possible
• 12 years agoHelpfull: Yes(1) No(1)
• not possible to distribute 5 prize among 6 when every child must get atleast one
• 12 years agoHelpfull: Yes(1) No(1)
• 6! way that means ans is 720
  
• 10 years agoHelpfull: Yes(1) No(3)
• 0 ways because 5 prizes and 6 children
• 9 years agoHelpfull: Yes(1) No(0)
• if the 5 and 6 is swapped as per the suggestion of Subrangsu Bhowmik
  5 prizes can be distribute to 5 children in 5! ways
  last (6th prize) can be distribute in 5 ways
  hence,
  -> 5! + 5 = 120+5 = 125
  125 ways :)
• 8 years agoHelpfull: Yes(1) No(0)
• it is not possible because every child should get atleast 1prize from the given condition so it is not possible
• 9 years agoHelpfull: Yes(0) No(1)
• There are five ways
  
  1st 1+1+1+1+2
  
  2nd 2+1+1+1+1
  
  3rd 1+2+1+1+1
  
  4th 1+1+2+1+1
  
  5th 1+1+1+2+1
• 4 years agoHelpfull: Yes(0) No(0)
• 6!*5=720*5=3600
• 2 Months agoHelpfull: Yes(0) No(0)