Which of the following has the most number of divisors?

A. 99 B. 101
C. 176 D. 182

• No. of divisors can be found out
  from the index of prime factors of that number
  99=3^2*11^1( No. of divisors=3*2=6)( simply increase 1 of the index of prime factor and multiply)
  101=No. of divisors=2 as the same is the prime No.
  176=2^4+11^1( No. of divisors=5*2=10
  182=2^1*7^1*13^1(No. of divisors=2*2*2=8
  Hence, 176 has 10 divisors
  
• 12 years agoHelpfull: Yes(3) No(0)
• C. 176 number have more number of divisors.
  
  Divisiors of 99 = 1, 3, 9, 11, 33, 99
  Divisors of 101 = 1,101
  Divisors of 176 = 1, 2, 4, 8, 11, 22, 44, 88, 176
  Divisors of 182 = 1, 2, 7, 13, 14, 26, 91, 182.
  
  So, C.176 is the answer
• 12 years agoHelpfull: Yes(2) No(1)