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Maths Puzzle
Logical Reasoning
Cryptography
The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:
A. 28 B. 32
C. 40 D. 64
Read Solution (Total 4)
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- Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x.
So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40. - 12 years agoHelpfull: Yes(15) No(1)
Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x.
So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.
ANS is C
- 12 years agoHelpfull: Yes(6) No(1)
- Option C
Explanation:
Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x.
So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40. - 11 years agoHelpfull: Yes(3) No(1)
- 2x*3x = 48
x=8
16:24 = 40 - 10 years agoHelpfull: Yes(1) No(1)
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