How many 9 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if the repetition is allowed?
a)5^7 b)5^6 c)5^9 d)5^8

• to be divisible by 4, last two digits must be divisible by 4. which are 12, 24, 32, 44, 52. so 5 combinations are possible for last two digits also 5 combinations each for remaining 7 places. so the answer is 5^8.
• 14 years agoHelpfull: Yes(18) No(5)
• First Consider 5 letters 1,2,3,4,5....
  So that the 9 digit number is divisible by 4... the 2 digit of 9 digit number should be divisible by 4, so we consider 8 digit..
  the solution is 8c5..
• 14 years agoHelpfull: Yes(7) No(7)
• 5^8
• 14 years agoHelpfull: Yes(4) No(1)
• 5^8
• 14 years agoHelpfull: Yes(3) No(1)
• 5^8
• 14 years agoHelpfull: Yes(3) No(1)
• 5^8=390625
• 14 years agoHelpfull: Yes(3) No(1)
• ANS: 5^8
• 14 years agoHelpfull: Yes(2) No(6)
• here is the condition is divisiable by 4 so last two digit are fix so that remainig are 5**7
• 2 years agoHelpfull: Yes(0) No(0)