how many 13 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if repetition of digits is allowed?

• same explanation as in Q1.
  answer is 5^12
• 14 years agoHelpfull: Yes(15) No(2)
• 5^12
• 14 years agoHelpfull: Yes(3) No(1)
• 5^12
• 14 years agoHelpfull: Yes(2) No(2)
• 5^12
• 14 years agoHelpfull: Yes(2) No(0)
• The given digits are 1,2,3,4,5
  For the number to be divisible by 4 we should have the last two digits to be a multiple of 4
  That is we should have the last two digits to be 2 and 4
  so let us write the last two digits of as 2 4
  now we are left with 11 places
  these places are to be filled with any of the digits 1,2,3,4,5
  so each place can be filled in 5 ways since repetition is allowed
  so we have 5 * 5* 5* .... 11 times
  so the total number = 5^11=48828125
  similarly the last two digits may be 12 and 44
  so with 12 and 44 also we get 5^11 = 48828125
  so total = 3* 48828125=146484375
  This is the final answer
• 9 years agoHelpfull: Yes(2) No(2)
• 5^11*5
  5^12
  
• 12 years agoHelpfull: Yes(0) No(0)