Two morning walkers start their walk together at a point with their right leg as the first step. They walk in such a manner that the first one takes 4 steps for every 7 steps of the second. How many steps would the second one take before they again take the right step together?

• The second one take 14 steps before they again take the right step together.
  Their odd step will be right while even step will be left. So both of them must have taken mininum number of even steps at the same time before taking right step together which is possible when first walker have taken 8(even) steps and second walker have taken 14 steps (even)
• 12 years agoHelpfull: Yes(8) No(4)
• The second one take 4 steps (i.e) 7 - 14 - 21 - 28 to take right step (because even numbers are right steps ) at the mean time first one takes 4 - 8 - 12 - 16 - 20 - 24 - 28
• 11 years agoHelpfull: Yes(2) No(0)
• difference between the two walker is 2 teps ie (7-4 =3 consider only how many steps are they taken ,so 2 steps would take by second one
  
• 12 years agoHelpfull: Yes(0) No(7)
• lcm of4,7 =28 that will we answer
  
• 10 years agoHelpfull: Yes(0) No(0)