How many 0's are there in the binary form of 6*1024 + 4*64 + 2

• 6*1024 + 4*64 + 2 = 6144+256 +2 = 6402
  
  in binary code
  6402 base 10 = 11001 000000 10 in base 2.
  
  so 9 zeros are there.
• 12 years agoHelpfull: Yes(7) No(0)
• 6*1024+4*64+2=6402
  6402 is converted into binary form which is(1100010000001)2
  .
  ..the total num of zeros in it are 9
  ans is 9
• 12 years agoHelpfull: Yes(2) No(0)
• 1024 has 10 0's
  6 has 1 zero
  1024*6=11 0's
  from 11 0's 256 cancels 1 zero & 2 cancels 1 zero on additn
  so, 11-1-1=9 zeros
• 11 years agoHelpfull: Yes(2) No(0)
• 9 zeros are in binary code of 6*1024 + 4*64 + 2
• 12 years agoHelpfull: Yes(1) No(1)
• 9 zeros
  1024*6 = 6144
  4*64 = 256
  so , 6144+256+2=6402
  (6402)base10 = (1 1001 0000 0010)base2
• 12 years agoHelpfull: Yes(0) No(0)
• getting sum 6402
  so in binary divide it by 2 modulo
  we get ans 1100100000010
  total zeros is 9
• 11 years agoHelpfull: Yes(0) No(0)
• 6402 = 11001 000000 10
  
  9 zeros
• 11 years agoHelpfull: Yes(0) No(0)