5,11,19,?,41

• Missing number is 29. The sequence is 5,11,19,29,41
  
  Explanation:
  Number to be added to get next number is incremented by 2 every time.
  i.e starting with 6, the number added to get next number is 8,10,12 and so on.
  this makes
  5+6 = 11
  11+8 = 19
  19+10 = 29
  29+12 = 41
  and so on...
• 12 years agoHelpfull: Yes(7) No(3)
• ans: 29 becoz 5+6=11
  11+8=19
  19+10=29
  29+12=41......... so the answer is 29
• 12 years agoHelpfull: Yes(1) No(1)
• 29...
  each time multiples of 2 are added to the number to get the next..
  5+6 =11
  11+8=19
  19+10=29
  29+12=41
• 12 years agoHelpfull: Yes(0) No(0)
• 11-5=6
  19-11=8
  29-19=10
  41-29=12
  and so on
  missing no. is 29
• 12 years agoHelpfull: Yes(0) No(0)
• The missing number is 29.
  
  Explanation.
  The numbers of the series are (n+1)^2 + n where n is a natural number 1,2,3,....
• 12 years agoHelpfull: Yes(0) No(0)
• there is a very silly logic behind it i.e
  add 6,8,10...to first,second ...as per sequence
• 12 years agoHelpfull: Yes(0) No(0)
• äns is 29
  the given series is 5,11,19,?,41
  it can be solved as follows*1+0^2 ,*2+1^2,*3+2^2,....
  5*1+0^2 , 5*2+1^2 , 5*3+2^2 , 5*4+3^2 , 5*5+4^2
  = 5 ,11, 19 , 29, 41
  the ans is "29"
  
• 12 years agoHelpfull: Yes(0) No(0)
• äns is 29
  the given series is 5,11,19,?,41
  it can be solved as follows*1+0^2 ,*2+1^2,*3+2^2,....
  5*1+0^2 , 5*2+1^2 , 5*3+2^2 , 5*4+3^2 , 5*5+4^2
  = 5 ,11, 19 , 29, 41
  the ans is "29"
  
• 12 years agoHelpfull: Yes(0) No(0)
• 29
  5+6=11
  11+8=19
  19+10=29
  29+12=41
• 12 years agoHelpfull: Yes(0) No(0)
• 29(5+6=11+8=19+10=29+12=41)
• 12 years agoHelpfull: Yes(0) No(0)
• 5+6=11
  11+(2+6)=19
  19+(2+8)=29
  29+(2+10)=41
  so the answer is 29
• 12 years agoHelpfull: Yes(0) No(0)
• 11-5=6
  19-11=8
  29-19=10
  41-29=12
• 12 years agoHelpfull: Yes(0) No(0)