CAT
Exam
A bucket in the form of a frustum of a right circular cone is 48 cm deep and the radii of the top and bottom are 20 cm and 16 cm respectively. The volume of water it will hold is
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- vol of water in bucket = (20^2+20*16+16^2)*Pi*48/3 = 976*16*pi Cubic cm
= 15616 *pi cubic cms - 12 years agoHelpfull: Yes(3) No(0)
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