on dividing a number by 5 ,we get 3 as remainder what will be the remainder when the square of this no. is divided by 5
a)0 b)1 c)2 d)4

• No is 5x+3
  Now
  (5x+3)^2 = 25x^2+30x+9= 5(5x^2+6x) +9
  First term is fully divisible by 5.
  when we divide 9 by 5, we get 4 as remainder.
  
  so 4 will be remainder.
• 12 years agoHelpfull: Yes(8) No(4)
• d) 4 is the remainder
  
  Dividing number by 5, we get 3 as remainder means,
  
  Original number as we divide by 5 is = 5+3 = 8
  
  So, square of 8 = 8^2 = 64
  
  Therefore, 64 divided by 5, we get remainder as 4.
• 12 years agoHelpfull: Yes(6) No(7)
• let x be the number and y be the quotient
  
  i.e x=5y+3
  
  x^2=(5y+3)^2
  
  x^2=25y^2+9+30y
  
  x^2=5(5y^2+6y+1)+4
  
  the remainder is 4
• 10 years agoHelpfull: Yes(0) No(1)