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Maths Puzzle
A snail creeps 7 ft up a wall during the daytime. After all the labor it does throughout the day, it stops to rest a while... but falls asleep!! The next morning it wakes up and discovers that it has slipped down 3 ft while sleeping.
If this happens every day, how many days will the snail take to reach the top of a wall 83 ft in height?
Read Solution (Total 3)
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- 21 days it take to reach.
On the first day, the snail climbs up 7 ft and slips down 3 ft while sleeping.
So, next morning, it is 4 ft from where it started. The snail thus travels 4 ft upwards every day. Therefore, in 20 days, it has traveled a distance of 80 ft from the bottom.
Here lies the catch to the problem!
On the last day, the snail travels 7 ft upwards and hence reaches the top of the wall in a total of 21 days. - 12 years agoHelpfull: Yes(1) No(0)
- Ans 20 days
snail's one day up creep 7-3=4 ft
After 19 days,it will be up by 19*4=76 ft
On 20th day it will reach 76+7=83 ft, at the top - 12 years agoHelpfull: Yes(1) No(3)
- 21 day he will take to reach.
- 12 years agoHelpfull: Yes(0) No(0)
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