CAT
Exam
Numerical Ability
Percentage
In an examination 70% candidates passed in English, 65% in Mathematics, 27% failed in both the subjects and 248 passed in both the subjects. Find the total number of candidates.
Read Solution (Total 3)
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- 400
If there are 100 candidates, then
candidates failed in english =30
candidates failed in Maths = 35
candidates failed in both = 27
candidates failed in atleast one subject = 30+35-27 = 38
candidates passed in both subjects = 62
If 62 candidates passed in both subjects, then total candidates = 100
If 248 candidates passed in both subjects, then total candidates = 100*248/62=400
- 12 years agoHelpfull: Yes(25) No(3)
- 400...
p=total no.of student
a=no.of student passed in eng=0.7p
b=no. of student passed in maths=0.65p
n(aUb)=n(a)+n(b)-n(aUb)
=1.35p-248
n(a'∩b')+n(aUb)=p
0.27p+1.35p-248=p
henc p=400
- 12 years agoHelpfull: Yes(8) No(2)
- 100 = 70%+65%-x+27
x=162%-100%=62%
62%=248
100%=x
by cross multiplying we get 400. - 5 years agoHelpfull: Yes(0) No(0)
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