CAT
Exam
Numerical Ability
Sequence and Series
The sum of the first and the 9th term of an arithmetic progression is 24. What is the sum of the first nine terms of the progression?
Read Solution (Total 3)
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- Sum of the first nine terms of the progression is 108.
** Sum of first 'n' terms of an A.P is = n/2(first term + last term)
where
n = number of terms
** Sum of the first 9 terms is = 9/2(first term + last term)
** Sum of the first 9 terms is = 9/2(24) ==> 108
where
first term + last term = 24 - 12 years agoHelpfull: Yes(3) No(1)
- sum of the first nine terms of the progression 24*9/2 = 108
- 12 years agoHelpfull: Yes(1) No(1)
- The sum S of the first n values of a finite sequence is given by the formula:
S = 1/2(a1 + an)n, where a1 is the first term and an the last.
given a1+an=24;
so,1/2(24)*9=108; - 12 years agoHelpfull: Yes(0) No(0)
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