If the sum of the squares of 3 consecutive natural numbers is 2030,Find these numbers?

• if numbers are x, x-1 , x+1
  (x-1)^2+(x)^2+(x+1)^2=2030
  3x^2+2= 2030
  3x^2= 2028
  x^2 = 676
  x= 26
  
  so numbers are 26,25,27 .. 25,26,27 in order.
• 12 years agoHelpfull: Yes(7) No(1)
• 25, 26, 27
  
  25^2 + 26^2 + 27^2
  625 +676 +729 =2030
• 12 years agoHelpfull: Yes(6) No(4)
• (x-1)square*(x)square*(x+1)square=2030 clearly xnot equql to 1.
  solving get 25,26and27
  
• 12 years agoHelpfull: Yes(1) No(3)
• a^2+(a+1)^2+(a+2)^2=2030
  a^2+2a-675=0
  (a+27)(a-25)=0
  a=25,-27
• 12 years agoHelpfull: Yes(1) No(4)
• if numbers are x, x-1 , x+1
  (x-1)^2+(x)^2+(x+1)^2=2030
  3x^2+2= 2030
  3x^2= 2028
  x^2 = 676
  x= 26
  
  so numbers are 26,25,27 .. 25,26,27 in order.
• 12 years agoHelpfull: Yes(1) No(2)
• (a-1)^2+a^2+(a+1)^2=2030
  a^2-2a+1+a^2+a^2+2a+1=2030
  3a^2+2=2030
  3a^2=2028
  a^2=676
  a = 26
  Numbers, 25,26,27
• 12 years agoHelpfull: Yes(1) No(1)
• x^2+(x+1)^2+(x+2)^2=2030
  x^2+2x-675=0
  (x+27)(x-25)
  ans:25
  
• 8 years agoHelpfull: Yes(0) No(0)