A number when divided by three consecutive numbers 9, 11, 13 leaves the remainders 8, 9 and 8 respectively. If the order of divisors is reversed, then what will be the remainders?

• Remainders are 8,9,8 only because let us assume that number is x and when the number is divided by 9,11,13 it leaves remainders 8,9,8 and given question is what will be the remainders if the number(x) is divided when the order of divisors is reversed i.e., 13,11,9 ---> from the first statement x/9 leaves remainder 8 like others also x/11-->9,x/13-->8 . So , if the number is divided by reversing the order i.e., x/13,x/11,x/9 leaves remainders 8,9,8 only......
  Thanks.
• 12 years agoHelpfull: Yes(4) No(4)
• Remainder are 2,1,6 respectively. Since no is divided by 9, 11,13 leaves the remainder 8,9,8 this no is 2160. by reversing the order of divisor we get remainder 2,1,6.
• 12 years agoHelpfull: Yes(1) No(15)