What is probability of 53 Sundays in a leap year?

• 2/7 or 0.2857 is the probability of 53 Sundays in a leap year.
  
  Leap year consist of 366 days.
  On that we have, 52 weeks and 2 days.
  
  That 2 days may be
  
  Sun,Mon
  Mon,Tue
  Tue,Wed
  Wed,Thu
  Thu,Fri
  Fri,Sat
  Sat,Sun
  
  We have 7 options.
  Among that we have to choose only 2 options which has Sundays. (i.e, [Sun Mon] or [Sat Sun]
  
  So that, the answer is 2/7 for having 53 Sundays.
• 12 years agoHelpfull: Yes(14) No(3)
• 2/7...................
• 12 years agoHelpfull: Yes(4) No(2)
• Ans. probability of 53 Sundays in a leap year = 2/7
  In leap year there are 52 full weeks and two days. The last two days can be in one of the following 7 pairs as:
  Saturday-Sunday, Sunday-Monday, Monday-Tuesday, Tuesday-Wednesday, Wednesday-Thursday, Thursday-Friday, Friday-Saturday.
  Here two pairs out of seven pairs contain Sunday.
  So probability of 53 Sundays in a leap year is = 2/7
  
• 12 years agoHelpfull: Yes(2) No(0)