How many two digit numbers increases by 18 when their digits are reversed?

• Let the two digit No. be xy(tens digit"x" and Units digit"y")
  then, the value of the two digit is 10x+y
  When the same is reversed, the value of the digit is 10y-x
  As per the condition:
  (10y-x)-(10x+y)=18
  which implies, 9(y-x)=18
  y-x=2
  Thus, the units digit is more than the Tens digit
  Thus, the numbers are:
  13,24,35,45,57,68,79( seven No. of two digits)
• 12 years agoHelpfull: Yes(4) No(1)
• 7 two digits numbers increases by 18 when their digits are reversed.
  
  They are,
  
  13, 24, 35, 45, 57, 68, 79,
• 12 years agoHelpfull: Yes(3) No(1)
• ans = 13,24,35, 46, 57,68,79. (total 7 case)
  let no. denoted as 10y+1x
  now reverse the no =10x+1y
  now difference b/w them (10y+1x)-(10x+1y)=18
  that is 9y-9x=18
  y-x=2 that equation shows that the in two digit no the diffrence bw x and y value should be two therefore no, are=13, 24,35,46,57,68,79.
  total 7 case.
• 12 years agoHelpfull: Yes(1) No(0)
• There was a typographicl mistake:
  Instead of putting 10y+x, I had put 10y-x
• 12 years agoHelpfull: Yes(0) No(1)
• we can calculate it directly there are 7 numbers they are 13, 24 ,35, 46, 57, 68, 79.
• 12 years agoHelpfull: Yes(0) No(0)
• 7 digits
  13, 24, 35, 46, 57, 68, 79
• 12 years agoHelpfull: Yes(0) No(0)