AIEEE
Exam
If a number is chosen at random from the set {1,2,3,.....,28,29,30}.What is the probability that
the number chosen is a product of exactly two different prime numbers?
Read Solution (Total 2)
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- Here, S = {1, 2, 3, 4, ...., 29, 30} = n(S) = 30
Let E = event of chosen a number which product is exactly two different prime numbers = {6, 10, 14, 15, 21, 22, 26} = n(E) = 7
p(E) = n(E)/ n(S) = 7/30 - 12 years agoHelpfull: Yes(5) No(0)
- probability that the number chosen is a product of exactly two different prime number = 7/30.
This is because only the numbers 6,10,14,15,21,22,26 are products of exactly two different prime number as 2*3,2*5,2*7,3*5,3*7,2*11,2*13. - 12 years agoHelpfull: Yes(2) No(0)
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