AIEEE
Exam
Numerical Ability
Arithmetic
A person is count 4500 notes(currency)
.If An denoted the no.of note he count in (n)min and if a1=a2=a3....a10=150 and a10,a11,a12............... are in A.P with common difference =-2. Find the time taken by him to count all the notes.
Read Solution (Total 1)
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- Total 34 mins
in 10 mins , 150*10=1500 notes are counted.
Balance 3000 notes are counted in next 24 minutes in AP
148,146,144,........ 102
If n mis are used to count 3000 notes, then
3000 = (n/2)*(2*148-2*(n-1)
solving it, we get , n=24 - 12 years agoHelpfull: Yes(3) No(4)
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